113134131444030 has 32 divisors (see below), whose sum is σ = 271522208653344. Its totient is φ = 30169069142016.

The previous prime is 113134131443891. The next prime is 113134131444127. The reversal of 113134131444030 is 30444131431311.

It is a junction number, because it is equal to n+sod(n) for n = 113134131443982 and 113134131444000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41403814 + ... + 44051606.

It is an arithmetic number, because the mean of its divisors is an integer number (8485069020417).

Almost surely, 2^{113134131444030} is an apocalyptic number.

113134131444030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113134131444030 is an abundant number, since it is smaller than the sum of its proper divisors (158388077209314).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113134131444030 is a wasteful number, since it uses less digits than its factorization.

113134131444030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4072060.

The product of its (nonzero) digits is 20736, while the sum is 33.

Adding to 113134131444030 its reverse (30444131431311), we get a palindrome (143578262875341).

The spelling of 113134131444030 in words is "one hundred thirteen trillion, one hundred thirty-four billion, one hundred thirty-one million, four hundred forty-four thousand, thirty".