Base | Representation |
---|---|
bin | 11001101110010100011101… |
… | …100111000011001111101111 |
3 | 112211120112020000211211102122 |
4 | 121232110131213003033233 |
5 | 104312042400430220421 |
6 | 1040341051540543155 |
7 | 32554451456623040 |
oct | 3156243547031757 |
9 | 484515200754378 |
10 | 113134230320111 |
11 | 33058a59681120 |
12 | 108322089b1abb |
13 | 4b18687239480 |
14 | 1dd1a2408c8c7 |
15 | d12d333882ab |
hex | 66e51d9c33ef |
113134230320111 has 32 divisors (see below), whose sum is σ = 152552438857728. Its totient is φ = 81026020304640.
The previous prime is 113134230319973. The next prime is 113134230320113. The reversal of 113134230320111 is 111023032431311.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113134230320111 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113134230320113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 242301551 + ... + 242768016.
It is an arithmetic number, because the mean of its divisors is an integer number (4767263714304).
Almost surely, 2113134230320111 is an apocalyptic number.
113134230320111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
113134230320111 is a deficient number, since it is larger than the sum of its proper divisors (39418208537617).
113134230320111 is a wasteful number, since it uses less digits than its factorization.
113134230320111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 485069831.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 113134230320111 its reverse (111023032431311), we get a palindrome (224157262751422).
The spelling of 113134230320111 in words is "one hundred thirteen trillion, one hundred thirty-four billion, two hundred thirty million, three hundred twenty thousand, one hundred eleven".
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