Base | Representation |
---|---|
bin | 10101000100101010… |
… | …11001111101000011 |
3 | 1002012110021001112201 |
4 | 22202111121331003 |
5 | 141132221024130 |
6 | 5110342334031 |
7 | 550233531400 |
oct | 124225317503 |
9 | 32173231481 |
10 | 11313454915 |
11 | 4886172144 |
12 | 2238a2a317 |
13 | 10b3b56729 |
14 | 7947872a7 |
15 | 463359bca |
hex | 2a2559f43 |
11313454915 has 24 divisors (see below), whose sum is σ = 16337244240. Its totient is φ = 7490282688.
The previous prime is 11313454903. The next prime is 11313454927. The reversal of 11313454915 is 51945431311.
11313454915 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (11313454903) and next prime (11313454927).
It is not a de Polignac number, because 11313454915 - 25 = 11313454883 is a prime.
It is a super-2 number, since 2×113134549152 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 789057 + ... + 803266.
It is an arithmetic number, because the mean of its divisors is an integer number (680718510).
Almost surely, 211313454915 is an apocalyptic number.
11313454915 is a deficient number, since it is larger than the sum of its proper divisors (5023789325).
11313454915 is a wasteful number, since it uses less digits than its factorization.
11313454915 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1592371 (or 1592364 counting only the distinct ones).
The product of its digits is 32400, while the sum is 37.
The spelling of 11313454915 in words is "eleven billion, three hundred thirteen million, four hundred fifty-four thousand, nine hundred fifteen".
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