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113140120411 = 197365298783
BaseRepresentation
bin110100101011110101…
…1010011101101011011
3101211000221002121210001
41221113223103231123
53323202332323121
6123550441233431
711113501104313
oct1512753235533
9354027077701
10113140120411
1143a8971504a
1219b16492877
13a890c31516
145694262443
152e22b18991
hex1a57ad3b5b

113140120411 has 8 divisors (see below), whose sum is σ = 113227692480. Its totient is φ = 113052582912.

The previous prime is 113140120397. The next prime is 113140120459. The reversal of 113140120411 is 114021041311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113140120411 - 27 = 113140120283 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113140120711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12877326 + ... + 12886108.

It is an arithmetic number, because the mean of its divisors is an integer number (14153461560).

Almost surely, 2113140120411 is an apocalyptic number.

113140120411 is a deficient number, since it is larger than the sum of its proper divisors (87572069).

113140120411 is an equidigital number, since it uses as much as digits as its factorization.

113140120411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17285.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 113140120411 its reverse (114021041311), we get a palindrome (227161161722).

The spelling of 113140120411 in words is "one hundred thirteen billion, one hundred forty million, one hundred twenty thousand, four hundred eleven".

Divisors: 1 1973 6529 8783 12881717 17328859 57344207 113140120411