1131402444135 has 8 divisors (see below), whose sum is σ = 1810243910640. Its totient is φ = 603414636864.

The previous prime is 1131402444119. The next prime is 1131402444181. The reversal of 1131402444135 is 5314442041311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1131402444135 - 2⁴ = 1131402444119 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131402444096 and 1131402444105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37713414790 + ... + 37713414819.

It is an arithmetic number, because the mean of its divisors is an integer number (226280488830).

Almost surely, 2^{1131402444135} is an apocalyptic number.

1131402444135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1131402444135 is a deficient number, since it is larger than the sum of its proper divisors (678841466505).

1131402444135 is an equidigital number, since it uses as much as digits as its factorization.

1131402444135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75426829617.

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 1131402444135 its reverse (5314442041311), we get a palindrome (6445844485446).

The spelling of 1131402444135 in words is "one trillion, one hundred thirty-one billion, four hundred two million, four hundred forty-four thousand, one hundred thirty-five".