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11314115 = 52262823
BaseRepresentation
bin101011001010…
…001111000011
3210021211001022
4223022033003
510344022430
61042300055
7165111521
oct53121703
923254038
1011314115
11642850a
12395762b
132461a57
141707311
15ed74e5
hexaca3c3

11314115 has 4 divisors (see below), whose sum is σ = 13576944. Its totient is φ = 9051288.

The previous prime is 11314111. The next prime is 11314123. The reversal of 11314115 is 51141311.

11314115 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11314115 - 22 = 11314111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11314093 and 11314102.

It is not an unprimeable number, because it can be changed into a prime (11314111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1131407 + ... + 1131416.

It is an arithmetic number, because the mean of its divisors is an integer number (3394236).

Almost surely, 211314115 is an apocalyptic number.

11314115 is a deficient number, since it is larger than the sum of its proper divisors (2262829).

11314115 is an equidigital number, since it uses as much as digits as its factorization.

11314115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2262828.

The product of its digits is 60, while the sum is 17.

The square root of 11314115 is about 3363.6460872095. The cubic root of 11314115 is about 224.4950982969.

Adding to 11314115 its reverse (51141311), we get a palindrome (62455426).

The spelling of 11314115 in words is "eleven million, three hundred fourteen thousand, one hundred fifteen".

Divisors: 1 5 2262823 11314115