Base | Representation |
---|---|
bin | 11001101110011010111111… |
… | …101011101011100011110111 |
3 | 112211121012022212002112001110 |
4 | 121232122333223223203313 |
5 | 104312201232032110403 |
6 | 1040344211541130103 |
7 | 32555120336455020 |
oct | 3156327753534367 |
9 | 484535285075043 |
10 | 113141244410103 |
11 | 33060a28979808 |
12 | 108336459b9933 |
13 | 4b19234436790 |
14 | 1dd20cb835c47 |
15 | d130e4037103 |
hex | 66e6bfaeb8f7 |
113141244410103 has 32 divisors (see below), whose sum is σ = 186328422346752. Its totient is φ = 59466517689600.
The previous prime is 113141244410027. The next prime is 113141244410141. The reversal of 113141244410103 is 301014442141311.
It is not a de Polignac number, because 113141244410103 - 28 = 113141244409847 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113141244410303) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 737355303 + ... + 737508728.
It is an arithmetic number, because the mean of its divisors is an integer number (5822763198336).
Almost surely, 2113141244410103 is an apocalyptic number.
113141244410103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
113141244410103 is a deficient number, since it is larger than the sum of its proper divisors (73187177936649).
113141244410103 is a wasteful number, since it uses less digits than its factorization.
113141244410103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1474864335.
The product of its (nonzero) digits is 4608, while the sum is 30.
Adding to 113141244410103 its reverse (301014442141311), we get a palindrome (414155686551414).
The spelling of 113141244410103 in words is "one hundred thirteen trillion, one hundred forty-one billion, two hundred forty-four million, four hundred ten thousand, one hundred three".
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