Base | Representation |
---|---|
bin | 10000011101101101110… |
… | …110001111110101110011 |
3 | 11000011101120002102010202 |
4 | 100131231312033311303 |
5 | 122014121322223201 |
6 | 2223433350545415 |
7 | 144512424451244 |
oct | 20355566176563 |
9 | 4004346072122 |
10 | 1131419336051 |
11 | 3a69177a0224 |
12 | 16333a06826b |
13 | 8290022bc94 |
14 | 3ca92218ccb |
15 | 1e66deddc6b |
hex | 1076dd8fd73 |
1131419336051 has 2 divisors, whose sum is σ = 1131419336052. Its totient is φ = 1131419336050.
The previous prime is 1131419336023. The next prime is 1131419336053. The reversal of 1131419336051 is 1506339141311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131419336051 is a prime.
Together with 1131419336053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1131419335996 and 1131419336014.
It is not a weakly prime, because it can be changed into another prime (1131419336053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565709668025 + 565709668026.
It is an arithmetic number, because the mean of its divisors is an integer number (565709668026).
Almost surely, 21131419336051 is an apocalyptic number.
1131419336051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131419336051 is an equidigital number, since it uses as much as digits as its factorization.
1131419336051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 29160, while the sum is 38.
The spelling of 1131419336051 in words is "one trillion, one hundred thirty-one billion, four hundred nineteen million, three hundred thirty-six thousand, fifty-one".
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