Base | Representation |
---|---|
bin | 1010010010100101000011… |
… | …1101000011110011010101 |
3 | 1111001122012011101200101220 |
4 | 2210221100331003303111 |
5 | 2440333142310310201 |
6 | 40021415115040553 |
7 | 2245300644355260 |
oct | 244512075036325 |
9 | 44048164350356 |
10 | 11314302041301 |
11 | 36724065a2556 |
12 | 1328954a40159 |
13 | 640c1b2c579c |
14 | 2b1887d35cd7 |
15 | 14949e760036 |
hex | a4a50f43cd5 |
11314302041301 has 8 divisors (see below), whose sum is σ = 17240841205824. Its totient is φ = 6465315452160.
The previous prime is 11314302041267. The next prime is 11314302041303. The reversal of 11314302041301 is 10314020341311.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11314302041301 - 217 = 11314301910229 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11314302041303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 269388143820 + ... + 269388143861.
It is an arithmetic number, because the mean of its divisors is an integer number (2155105150728).
Almost surely, 211314302041301 is an apocalyptic number.
It is an amenable number.
11314302041301 is a deficient number, since it is larger than the sum of its proper divisors (5926539164523).
11314302041301 is an equidigital number, since it uses as much as digits as its factorization.
11314302041301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 538776287691.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 11314302041301 its reverse (10314020341311), we get a palindrome (21628322382612).
The spelling of 11314302041301 in words is "eleven trillion, three hundred fourteen billion, three hundred two million, forty-one thousand, three hundred one".
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