Base | Representation |
---|---|
bin | 11001101110011100101010… |
… | …010111010101110101001111 |
3 | 112211121100221120222022120001 |
4 | 121232130222113111311033 |
5 | 104312213413231142320 |
6 | 1040345105315305131 |
7 | 32555212601664661 |
oct | 3156345227256517 |
9 | 484540846868501 |
10 | 113143034240335 |
11 | 33061767217750 |
12 | 10833a652ab1a7 |
13 | 4b1945b1a5918 |
14 | 1dd221b422531 |
15 | d1319b23220a |
hex | 66e72a5d5d4f |
113143034240335 has 32 divisors (see below), whose sum is σ = 156029308819200. Its totient is φ = 77895364066560.
The previous prime is 113143034240231. The next prime is 113143034240377. The reversal of 113143034240335 is 533042430341311.
It is not a de Polignac number, because 113143034240335 - 223 = 113143025851727 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113143034240294 and 113143034240303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 40053790 + ... + 42785419.
It is an arithmetic number, because the mean of its divisors is an integer number (4875915900600).
Almost surely, 2113143034240335 is an apocalyptic number.
113143034240335 is a deficient number, since it is larger than the sum of its proper divisors (42886274578865).
113143034240335 is a wasteful number, since it uses less digits than its factorization.
113143034240335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82840551.
The product of its (nonzero) digits is 155520, while the sum is 37.
Adding to 113143034240335 its reverse (533042430341311), we get a palindrome (646185464581646).
The spelling of 113143034240335 in words is "one hundred thirteen trillion, one hundred forty-three billion, thirty-four million, two hundred forty thousand, three hundred thirty-five".
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