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1131432035 = 5226286407
BaseRepresentation
bin100001101110000…
…0100100001100011
32220211222200222012
41003130010201203
54304121311120
6304134303135
740016004446
oct10334044143
92824880865
101131432035
115307336a8
12276ab7aab
13150537716
14aa3a165d
15694e41c5
hex43704863

1131432035 has 4 divisors (see below), whose sum is σ = 1357718448. Its totient is φ = 905145624.

The previous prime is 1131431993. The next prime is 1131432047. The reversal of 1131432035 is 5302341311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5302341311 = 14243372277.

It is a cyclic number.

It is not a de Polignac number, because 1131432035 - 216 = 1131366499 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1131432035.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113143199 + ... + 113143208.

It is an arithmetic number, because the mean of its divisors is an integer number (339429612).

Almost surely, 21131432035 is an apocalyptic number.

1131432035 is a deficient number, since it is larger than the sum of its proper divisors (226286413).

1131432035 is an equidigital number, since it uses as much as digits as its factorization.

1131432035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 226286412.

The product of its (nonzero) digits is 1080, while the sum is 23.

The square root of 1131432035 is about 33636.7661198279. The cubic root of 1131432035 is about 1042.0202455655.

Adding to 1131432035 its reverse (5302341311), we get a palindrome (6433773346).

The spelling of 1131432035 in words is "one billion, one hundred thirty-one million, four hundred thirty-two thousand, thirty-five".

Divisors: 1 5 226286407 1131432035