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11314322111 = 27294145959
BaseRepresentation
bin10101000100110001…
…01101101010111111
31002012111220010010002
422202120231222333
5141132431301421
65110413104515
7550244102561
oct124230555277
932174803102
1011314322111
114886704734
12223918813b
1310b409b371
14794931331
1546347bb0b
hex2a262dabf

11314322111 has 4 divisors (see below), whose sum is σ = 11318470800. Its totient is φ = 11310173424.

The previous prime is 11314322099. The next prime is 11314322119. The reversal of 11314322111 is 11122341311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11122341311 = 23483580057.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11314322111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11314322119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2070251 + ... + 2075708.

It is an arithmetic number, because the mean of its divisors is an integer number (2829617700).

Almost surely, 211314322111 is an apocalyptic number.

11314322111 is a deficient number, since it is larger than the sum of its proper divisors (4148689).

11314322111 is an equidigital number, since it uses as much as digits as its factorization.

11314322111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4148688.

The product of its digits is 144, while the sum is 20.

Adding to 11314322111 its reverse (11122341311), we get a palindrome (22436663422).

The spelling of 11314322111 in words is "eleven billion, three hundred fourteen million, three hundred twenty-two thousand, one hundred eleven".

Divisors: 1 2729 4145959 11314322111