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1131433053141 = 3385397883299
BaseRepresentation
bin10000011101101110101…
…010100100101111010101
311000011102111220022110010
4100131232222210233111
5122014133330200031
62223435000550433
7144512652161616
oct20355652445725
94004374808403
101131433053141
113a692450a066
12163342782419
13829030226c1
143ca93d89c0d
151e6702ed246
hex1076eaa4bd5

1131433053141 has 8 divisors (see below), whose sum is σ = 1508968952800. Its totient is φ = 754092927792.

The previous prime is 1131433053133. The next prime is 1131433053151. The reversal of 1131433053141 is 1413503341311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1131433053141 - 23 = 1131433053133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131433053099 and 1131433053108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131433053151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48930091 + ... + 48953208.

It is an arithmetic number, because the mean of its divisors is an integer number (188621119100).

Almost surely, 21131433053141 is an apocalyptic number.

It is an amenable number.

1131433053141 is a deficient number, since it is larger than the sum of its proper divisors (377535899659).

1131433053141 is an equidigital number, since it uses as much as digits as its factorization.

1131433053141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97887155.

The product of its (nonzero) digits is 6480, while the sum is 30.

Adding to 1131433053141 its reverse (1413503341311), we get a palindrome (2544936394452).

The spelling of 1131433053141 in words is "one trillion, one hundred thirty-one billion, four hundred thirty-three million, fifty-three thousand, one hundred forty-one".

Divisors: 1 3 3853 11559 97883299 293649897 377144351047 1131433053141