Search a number
-
+
1131443000477 is a prime number
BaseRepresentation
bin10000011101101111010…
…000100001010010011101
311000011110012121200121222
4100131233100201102131
5122014143402003402
62223435554103125
7144513132551606
oct20355720412235
94004405550558
101131443000477
113a692a0936a9
12163345b7aaa5
13829050c62ba
143ca95418dad
151e6711157a2
hex1076f42149d

1131443000477 has 2 divisors, whose sum is σ = 1131443000478. Its totient is φ = 1131443000476.

The previous prime is 1131443000399. The next prime is 1131443000483. The reversal of 1131443000477 is 7740003441311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 618709669561 + 512733330916 = 786581^2 + 716054^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131443000477 - 220 = 1131441951901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131443002477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565721500238 + 565721500239.

It is an arithmetic number, because the mean of its divisors is an integer number (565721500239).

Almost surely, 21131443000477 is an apocalyptic number.

It is an amenable number.

1131443000477 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131443000477 is an equidigital number, since it uses as much as digits as its factorization.

1131443000477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28224, while the sum is 35.

Adding to 1131443000477 its reverse (7740003441311), we get a palindrome (8871446441788).

The spelling of 1131443000477 in words is "one trillion, one hundred thirty-one billion, four hundred forty-three million, four hundred seventy-seven", and thus it is an aban number.