Base | Representation |
---|---|
bin | 10101000100110010… |
… | …01001000011111101 |
3 | 1002012112002211000021 |
4 | 22202121021003331 |
5 | 141132443344201 |
6 | 5110415332141 |
7 | 550245050632 |
oct | 124231110375 |
9 | 32175084007 |
10 | 11314434301 |
11 | 4886780a55 |
12 | 2239221051 |
13 | 10b410a451 |
14 | 794960189 |
15 | 46349eea1 |
hex | 2a26490fd |
11314434301 has 4 divisors (see below), whose sum is σ = 11319423100. Its totient is φ = 11309445504.
The previous prime is 11314434289. The next prime is 11314434319. The reversal of 11314434301 is 10343441311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3398773401 + 7915660900 = 58299^2 + 88970^2 .
It is a cyclic number.
It is not a de Polignac number, because 11314434301 - 29 = 11314433789 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11314434701) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2490996 + ... + 2495533.
It is an arithmetic number, because the mean of its divisors is an integer number (2829855775).
Almost surely, 211314434301 is an apocalyptic number.
It is an amenable number.
11314434301 is a deficient number, since it is larger than the sum of its proper divisors (4988799).
11314434301 is an equidigital number, since it uses as much as digits as its factorization.
11314434301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4988798.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11314434301 its reverse (10343441311), we get a palindrome (21657875612).
The spelling of 11314434301 in words is "eleven billion, three hundred fourteen million, four hundred thirty-four thousand, three hundred one".
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