113151544001 has 2 divisors, whose sum is σ = 113151544002. Its totient is φ = 113151544000.

The previous prime is 113151543983. The next prime is 113151544003. The reversal of 113151544001 is 100445151311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113151504400 + 39601 = 336380^2 + 199^2 .

It is a cyclic number.

It is not a de Polignac number, because 113151544001 - 2¹⁸ = 113151281857 is a prime.

Together with 113151544003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113151544003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56575772000 + 56575772001.

It is an arithmetic number, because the mean of its divisors is an integer number (56575772001).

Almost surely, 2^113151544001 is an apocalyptic number.

It is an amenable number.

113151544001 is a deficient number, since it is larger than the sum of its proper divisors (1).

113151544001 is an equidigital number, since it uses as much as digits as its factorization.

113151544001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 113151544001 its reverse (100445151311), we get a palindrome (213596695312).

The spelling of 113151544001 in words is "one hundred thirteen billion, one hundred fifty-one million, five hundred forty-four thousand, one".