113152124400331 has 4 divisors (see below), whose sum is σ = 113152295562912. Its totient is φ = 113151953237752.

The previous prime is 113152124400317. The next prime is 113152124400389. The reversal of 113152124400331 is 133004421251311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113152124400331 - 2¹¹ = 113152124398283 is a prime.

It is a super-2 number, since 2×113152124400331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113152124400293 and 113152124400302.

It is not an unprimeable number, because it can be changed into a prime (113152124400391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84585811 + ... + 85913116.

It is an arithmetic number, because the mean of its divisors is an integer number (28288073890728).

Almost surely, 2^{113152124400331} is an apocalyptic number.

113152124400331 is a deficient number, since it is larger than the sum of its proper divisors (171162581).

113152124400331 is an equidigital number, since it uses as much as digits as its factorization.

113152124400331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171162580.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 113152124400331 its reverse (133004421251311), we get a palindrome (246156545651642).

The spelling of 113152124400331 in words is "one hundred thirteen trillion, one hundred fifty-two billion, one hundred twenty-four million, four hundred thousand, three hundred thirty-one".