Base | Representation |
---|---|
bin | 10101000100111000… |
… | …10100011100011001 |
3 | 1002012120200010202001 |
4 | 22202130110130121 |
5 | 141133202023403 |
6 | 5110445241001 |
7 | 550255120435 |
oct | 124234243431 |
9 | 32176603661 |
10 | 11315267353 |
11 | 488719a925 |
12 | 2239563161 |
13 | 10b433c690 |
14 | 794ad99c5 |
15 | 4635b6c1d |
hex | 2a2714719 |
11315267353 has 8 divisors (see below), whose sum is σ = 12827024000. Its totient is φ = 9895132368.
The previous prime is 11315267351. The next prime is 11315267393. The reversal of 11315267353 is 35376251311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11315267353 - 21 = 11315267351 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11315267351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22905153 + ... + 22905646.
It is an arithmetic number, because the mean of its divisors is an integer number (1603378000).
Almost surely, 211315267353 is an apocalyptic number.
11315267353 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11315267353 is a deficient number, since it is larger than the sum of its proper divisors (1511756647).
11315267353 is a wasteful number, since it uses less digits than its factorization.
11315267353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45810831.
The product of its digits is 56700, while the sum is 37.
The spelling of 11315267353 in words is "eleven billion, three hundred fifteen million, two hundred sixty-seven thousand, three hundred fifty-three".
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