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1131624963013 is a prime number
BaseRepresentation
bin10000011101111010000…
…110101001101111000101
311000011220220000100022011
4100131322012221233011
5122020031442304023
62223510014134221
7144520502322616
oct20357206515705
94004826010264
101131624963013
113a6a12876866
12163396ab1371
1382933a0653c
143cab1663c0d
151e6820aa50d
hex1077a1a9bc5

1131624963013 has 2 divisors, whose sum is σ = 1131624963014. Its totient is φ = 1131624963012.

The previous prime is 1131624963011. The next prime is 1131624963047. The reversal of 1131624963013 is 3103694261311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 706596591649 + 425028371364 = 840593^2 + 651942^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131624963013 - 21 = 1131624963011 is a prime.

Together with 1131624963011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131624963011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565812481506 + 565812481507.

It is an arithmetic number, because the mean of its divisors is an integer number (565812481507).

Almost surely, 21131624963013 is an apocalyptic number.

It is an amenable number.

1131624963013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131624963013 is an equidigital number, since it uses as much as digits as its factorization.

1131624963013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 40.

The spelling of 1131624963013 in words is "one trillion, one hundred thirty-one billion, six hundred twenty-four million, nine hundred sixty-three thousand, thirteen".