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1132000121303 = 9967113574809
BaseRepresentation
bin10000011110010000011…
…101110001000111010111
311000012220000221100201122
4100132100131301013113
5122021314012340203
62224011135114155
7144533006161562
oct20362035610727
94005800840648
101132000121303
113a7095614837
1216348067295b
138299365a9ac
143cb093dd4d9
151e6a4eb3538
hex107907711d7

1132000121303 has 4 divisors (see below), whose sum is σ = 1132113706080. Its totient is φ = 1131886536528.

The previous prime is 1132000121143. The next prime is 1132000121309. The reversal of 1132000121303 is 3031210002311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1132000121303 - 214 = 1132000104919 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1132000121309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56777438 + ... + 56797371.

It is an arithmetic number, because the mean of its divisors is an integer number (283028426520).

Almost surely, 21132000121303 is an apocalyptic number.

1132000121303 is a deficient number, since it is larger than the sum of its proper divisors (113584777).

1132000121303 is an equidigital number, since it uses as much as digits as its factorization.

1132000121303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113584776.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1132000121303 its reverse (3031210002311), we get a palindrome (4163210123614).

The spelling of 1132000121303 in words is "one trillion, one hundred thirty-two billion, one hundred twenty-one thousand, three hundred three".

Divisors: 1 9967 113574809 1132000121303