1132000131001 has 2 divisors, whose sum is σ = 1132000131002. Its totient is φ = 1132000131000.

The previous prime is 1132000130999. The next prime is 1132000131043. The reversal of 1132000131001 is 1001310002311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1131934277776 + 65853225 = 1063924^2 + 8115^2 .

It is a cyclic number.

It is not a de Polignac number, because 1132000131001 - 2¹ = 1132000130999 is a prime.

It is a super-2 number, since 2×1132000131001² (a number of 25 digits) contains 22 as substring.

Together with 1132000130999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1132000131061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566000065500 + 566000065501.

It is an arithmetic number, because the mean of its divisors is an integer number (566000065501).

Almost surely, 2^{1132000131001} is an apocalyptic number.

It is an amenable number.

1132000131001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1132000131001 is an equidigital number, since it uses as much as digits as its factorization.

1132000131001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1132000131001 its reverse (1001310002311), we get a palindrome (2133310133312).

The spelling of 1132000131001 in words is "one trillion, one hundred thirty-two billion, one hundred thirty-one thousand, one".