113200013110031 has 4 divisors (see below), whose sum is σ = 113894491718232. Its totient is φ = 112505534501832.

The previous prime is 113200013110027. The next prime is 113200013110087. The reversal of 113200013110031 is 130011310002311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113200013110031 - 2² = 113200013110027 is a prime.

It is a super-2 number, since 2×113200013110031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113200013109991 and 113200013110009.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113200013115031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 347239303856 + ... + 347239304181.

It is an arithmetic number, because the mean of its divisors is an integer number (28473622929558).

Almost surely, 2^{113200013110031} is an apocalyptic number.

113200013110031 is a deficient number, since it is larger than the sum of its proper divisors (694478608201).

113200013110031 is an equidigital number, since it uses as much as digits as its factorization.

113200013110031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 694478608200.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 113200013110031 its reverse (130011310002311), we get a palindrome (243211323112342).

The spelling of 113200013110031 in words is "one hundred thirteen trillion, two hundred billion, thirteen million, one hundred ten thousand, thirty-one".