Base | Representation |
---|---|
bin | 1010010010111010010100… |
… | …1100010101111001011111 |
3 | 1111002011220222111022122122 |
4 | 2210232211030111321133 |
5 | 2440431340114113043 |
6 | 40024201350533155 |
7 | 2245562256645014 |
oct | 244564514257137 |
9 | 44064828438578 |
10 | 11320010301023 |
11 | 3674875780576 |
12 | 1329a886671bb |
13 | 64161aac6168 |
14 | 2b1c6a0c170b |
15 | 1496d596b368 |
hex | a4ba5315e5f |
11320010301023 has 2 divisors, whose sum is σ = 11320010301024. Its totient is φ = 11320010301022.
The previous prime is 11320010301001. The next prime is 11320010301029. The reversal of 11320010301023 is 32010301002311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11320010301023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11320010300992 and 11320010301010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11320010301029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660005150511 + 5660005150512.
It is an arithmetic number, because the mean of its divisors is an integer number (5660005150512).
Almost surely, 211320010301023 is an apocalyptic number.
11320010301023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11320010301023 is an equidigital number, since it uses as much as digits as its factorization.
11320010301023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11320010301023 its reverse (32010301002311), we get a palindrome (43330311303334).
The spelling of 11320010301023 in words is "eleven trillion, three hundred twenty billion, ten million, three hundred one thousand, twenty-three".
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