Base | Representation |
---|---|
bin | 110100101101101000… |
… | …0111100111001111010 |
3 | 101211012010101002020222 |
4 | 1221123100330321322 |
5 | 3323313240220442 |
6 | 124000431420042 |
7 | 11115131562551 |
oct | 1513320747172 |
9 | 354163332228 |
10 | 113200320122 |
11 | 4400a6a1a7a |
12 | 19b32684622 |
13 | a8a054b356 |
14 | 569c252d98 |
15 | 2e2805a8d2 |
hex | 1a5b43ce7a |
113200320122 has 4 divisors (see below), whose sum is σ = 169800480186. Its totient is φ = 56600160060.
The previous prime is 113200320113. The next prime is 113200320169. The reversal of 113200320122 is 221023002311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 93141546481 + 20058773641 = 305191^2 + 141629^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 113200320122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28300080029 + ... + 28300080032.
Almost surely, 2113200320122 is an apocalyptic number.
113200320122 is a deficient number, since it is larger than the sum of its proper divisors (56600160064).
113200320122 is an equidigital number, since it uses as much as digits as its factorization.
113200320122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56600160063.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 113200320122 its reverse (221023002311), we get a palindrome (334223322433).
The spelling of 113200320122 in words is "one hundred thirteen billion, two hundred million, three hundred twenty thousand, one hundred twenty-two".
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