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113200320122 = 256600160061
BaseRepresentation
bin110100101101101000…
…0111100111001111010
3101211012010101002020222
41221123100330321322
53323313240220442
6124000431420042
711115131562551
oct1513320747172
9354163332228
10113200320122
114400a6a1a7a
1219b32684622
13a8a054b356
14569c252d98
152e2805a8d2
hex1a5b43ce7a

113200320122 has 4 divisors (see below), whose sum is σ = 169800480186. Its totient is φ = 56600160060.

The previous prime is 113200320113. The next prime is 113200320169. The reversal of 113200320122 is 221023002311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 93141546481 + 20058773641 = 305191^2 + 141629^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 113200320122.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28300080029 + ... + 28300080032.

Almost surely, 2113200320122 is an apocalyptic number.

113200320122 is a deficient number, since it is larger than the sum of its proper divisors (56600160064).

113200320122 is an equidigital number, since it uses as much as digits as its factorization.

113200320122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56600160063.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 113200320122 its reverse (221023002311), we get a palindrome (334223322433).

The spelling of 113200320122 in words is "one hundred thirteen billion, two hundred million, three hundred twenty thousand, one hundred twenty-two".

Divisors: 1 2 56600160061 113200320122