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113200370147 is a prime number
BaseRepresentation
bin110100101101101000…
…1001001000111100011
3101211012010110121212202
41221123101021013203
53323313243321042
6124000432443415
711115132161444
oct1513321110743
9354163417782
10113200370147
114400a726617
1219b326a956b
13a8a0568057
14569c2672cb
152e2806a632
hex1a5b4491e3

113200370147 has 2 divisors, whose sum is σ = 113200370148. Its totient is φ = 113200370146.

The previous prime is 113200370093. The next prime is 113200370149. The reversal of 113200370147 is 741073002311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113200370147 is a prime.

Together with 113200370149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113200370149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600185073 + 56600185074.

It is an arithmetic number, because the mean of its divisors is an integer number (56600185074).

Almost surely, 2113200370147 is an apocalyptic number.

113200370147 is a deficient number, since it is larger than the sum of its proper divisors (1).

113200370147 is an equidigital number, since it uses as much as digits as its factorization.

113200370147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3528, while the sum is 29.

Adding to 113200370147 its reverse (741073002311), we get a palindrome (854273372458).

The spelling of 113200370147 in words is "one hundred thirteen billion, two hundred million, three hundred seventy thousand, one hundred forty-seven".