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11320041412343 = 13038687675681
BaseRepresentation
bin1010010010111010011100…
…0011000001011011110111
31111002012000011000221100202
42210232213003001123313
52440431421100143333
640024204421431115
72245563115252406
oct244564703013367
944065004027322
1011320041412343
11367489129aa04
121329a96b6b49b
13641624399c21
142b1c7029d63d
151496d85645e8
hexa4ba70c16f7

11320041412343 has 4 divisors (see below), whose sum is σ = 11328729089328. Its totient is φ = 11311353735360.

The previous prime is 11320041412291. The next prime is 11320041412397. The reversal of 11320041412343 is 34321414002311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11320041412343 - 26 = 11320041412279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11320041412543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4343836538 + ... + 4343839143.

It is an arithmetic number, because the mean of its divisors is an integer number (2832182272332).

Almost surely, 211320041412343 is an apocalyptic number.

11320041412343 is a deficient number, since it is larger than the sum of its proper divisors (8687676985).

11320041412343 is an equidigital number, since it uses as much as digits as its factorization.

11320041412343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8687676984.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 11320041412343 its reverse (34321414002311), we get a palindrome (45641455414654).

The spelling of 11320041412343 in words is "eleven trillion, three hundred twenty billion, forty-one million, four hundred twelve thousand, three hundred forty-three".

Divisors: 1 1303 8687675681 11320041412343