11320120000001 has 4 divisors (see below), whose sum is σ = 11406533129904. Its totient is φ = 11233706870100.

The previous prime is 11320119999997. The next prime is 11320120000031. The reversal of 11320120000001 is 10000002102311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11320120000001 - 2² = 11320119999997 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11320120000031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43206564755 + ... + 43206565016.

It is an arithmetic number, because the mean of its divisors is an integer number (2851633282476).

Almost surely, 2^{11320120000001} is an apocalyptic number.

It is an amenable number.

11320120000001 is a deficient number, since it is larger than the sum of its proper divisors (86413129903).

11320120000001 is an equidigital number, since it uses as much as digits as its factorization.

11320120000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86413129902.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 11320120000001 its reverse (10000002102311), we get a palindrome (21320122102312).

The spelling of 11320120000001 in words is "eleven trillion, three hundred twenty billion, one hundred twenty million, one", and thus it is an aban number.