Base | Representation |
---|---|
bin | 10000011110010001001… |
… | …011001010010111100111 |
3 | 11000012220212022221100102 |
4 | 100132101023022113213 |
5 | 122021330034134343 |
6 | 2224012242134315 |
7 | 144533212263326 |
oct | 20362113122747 |
9 | 4005825287312 |
10 | 1132012021223 |
11 | 3a70a1302386 |
12 | 16348465139b |
13 | 82995c66275 |
14 | 3cb0ac1a0bd |
15 | 1e6a60643b8 |
hex | 107912ca5e7 |
1132012021223 has 2 divisors, whose sum is σ = 1132012021224. Its totient is φ = 1132012021222.
The previous prime is 1132012021213. The next prime is 1132012021271. The reversal of 1132012021223 is 3221202102311.
It is a weak prime.
It is an emirp because it is prime and its reverse (3221202102311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1132012021223 - 28 = 1132012020967 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1132012021195 and 1132012021204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1132012021213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566006010611 + 566006010612.
It is an arithmetic number, because the mean of its divisors is an integer number (566006010612).
Almost surely, 21132012021223 is an apocalyptic number.
1132012021223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132012021223 is an equidigital number, since it uses as much as digits as its factorization.
1132012021223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 1132012021223 its reverse (3221202102311), we get a palindrome (4353214123534).
The spelling of 1132012021223 in words is "one trillion, one hundred thirty-two billion, twelve million, twenty-one thousand, two hundred twenty-three".
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