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11320122000023 is a prime number
BaseRepresentation
bin1010010010111010101111…
…0110011100001010010111
31111002012012202200012212122
42210232223312130022113
52440432102213000043
640024220421010155
72245565114244044
oct244565366341227
944065182605778
1011320122000023
1136749228326a1
121329ab9b5395b
13641637ca4945
142b1c7ac7a1cb
151496e0682368
hexa4babd9c297

11320122000023 has 2 divisors, whose sum is σ = 11320122000024. Its totient is φ = 11320122000022.

The previous prime is 11320121999971. The next prime is 11320122000049. The reversal of 11320122000023 is 32000022102311.

It is a strong prime.

It is an emirp because it is prime and its reverse (32000022102311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11320122000023 is a prime.

It is a super-2 number, since 2×113201220000232 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11320121999965 and 11320122000010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11320122002023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660061000011 + 5660061000012.

It is an arithmetic number, because the mean of its divisors is an integer number (5660061000012).

Almost surely, 211320122000023 is an apocalyptic number.

11320122000023 is a deficient number, since it is larger than the sum of its proper divisors (1).

11320122000023 is an equidigital number, since it uses as much as digits as its factorization.

11320122000023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11320122000023 its reverse (32000022102311), we get a palindrome (43320144102334).

The spelling of 11320122000023 in words is "eleven trillion, three hundred twenty billion, one hundred twenty-two million, twenty-three", and thus it is an aban number.