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113201222447 = 313651652337
BaseRepresentation
bin110100101101101010…
…0011001001100101111
3101211012012001221000102
41221123110121030233
53323314003104242
6124000503021315
711115142341335
oct1513324311457
9354165057012
10113201222447
11440101589a5
1219b32a3a83b
13a8a07a5c81
14569c409b55
152e28187e32
hex1a5b51932f

113201222447 has 4 divisors (see below), whose sum is σ = 116852874816. Its totient is φ = 109549570080.

The previous prime is 113201222443. The next prime is 113201222461. The reversal of 113201222447 is 744222102311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113201222447 - 22 = 113201222443 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113201222443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1825826138 + ... + 1825826199.

It is an arithmetic number, because the mean of its divisors is an integer number (29213218704).

Almost surely, 2113201222447 is an apocalyptic number.

113201222447 is a deficient number, since it is larger than the sum of its proper divisors (3651652369).

113201222447 is an equidigital number, since it uses as much as digits as its factorization.

113201222447 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3651652368.

The product of its (nonzero) digits is 5376, while the sum is 29.

Adding to 113201222447 its reverse (744222102311), we get a palindrome (857423324758).

The spelling of 113201222447 in words is "one hundred thirteen billion, two hundred one million, two hundred twenty-two thousand, four hundred forty-seven".

Divisors: 1 31 3651652337 113201222447