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11320130101 = 71617161443
BaseRepresentation
bin10101000101011101…
…10111101000110101
31002012220211012011211
422202232313220311
5141140423130401
65111141401421
7550344342520
oct124256675065
932186735154
1011320130101
114889a11325
12223b109271
1310b5352b47
14795603bb7
15463c27951
hex2a2bb7a35

11320130101 has 4 divisors (see below), whose sum is σ = 12937291552. Its totient is φ = 9702968652.

The previous prime is 11320130011. The next prime is 11320130149. The reversal of 11320130101 is 10103102311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11320130101 - 29 = 11320129589 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11320130161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808580715 + ... + 808580728.

It is an arithmetic number, because the mean of its divisors is an integer number (3234322888).

Almost surely, 211320130101 is an apocalyptic number.

It is an amenable number.

11320130101 is a deficient number, since it is larger than the sum of its proper divisors (1617161451).

11320130101 is an equidigital number, since it uses as much as digits as its factorization.

11320130101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1617161450.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11320130101 its reverse (10103102311), we get a palindrome (21423232412).

The spelling of 11320130101 in words is "eleven billion, three hundred twenty million, one hundred thirty thousand, one hundred one".

Divisors: 1 7 1617161443 11320130101