Base | Representation |
---|---|
bin | 10000011110010001001… |
… | …111101111000010101101 |
3 | 11000012220221120211210001 |
4 | 100132101033233002231 |
5 | 122021330341020023 |
6 | 2224012323544301 |
7 | 144533225415334 |
oct | 20362117570255 |
9 | 4005827524701 |
10 | 1132013220013 |
11 | 3a70a1a51015 |
12 | 163484b2b091 |
13 | 82996295b00 |
14 | 3cb0b04cd1b |
15 | 1e6a61ee6ad |
hex | 107913ef0ad |
1132013220013 has 12 divisors (see below), whose sum is σ = 1226300860800. Its totient is φ = 1044499334736.
The previous prime is 1132013219971. The next prime is 1132013220061. The reversal of 1132013220013 is 3100223102311.
It is not a de Polignac number, because 1132013220013 - 237 = 994574266541 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1132013220713) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 990631 + ... + 1801492.
It is an arithmetic number, because the mean of its divisors is an integer number (102191738400).
Almost surely, 21132013220013 is an apocalyptic number.
1132013220013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1132013220013 is a deficient number, since it is larger than the sum of its proper divisors (94287640787).
1132013220013 is a wasteful number, since it uses less digits than its factorization.
1132013220013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2794548 (or 2794535 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1132013220013 its reverse (3100223102311), we get a palindrome (4232236322324).
The spelling of 1132013220013 in words is "one trillion, one hundred thirty-two billion, thirteen million, two hundred twenty thousand, thirteen".
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