Base | Representation |
---|---|
bin | 10000011110010001010… |
… | …000000101000000110000 |
3 | 11000012220221202102012220 |
4 | 100132101100011000300 |
5 | 122021330401410000 |
6 | 2224012325521040 |
7 | 144533226241566 |
oct | 20362120050060 |
9 | 4005827672186 |
10 | 1132013310000 |
11 | 3a70a2002691 |
12 | 163484b73180 |
13 | 829962c7a61 |
14 | 3cb0b073a36 |
15 | 1e6a621b1a0 |
hex | 10791405030 |
1132013310000 has 200 divisors, whose sum is σ = 3813174393600. Its totient is φ = 288745248000.
The previous prime is 1132013309969. The next prime is 1132013310013. The reversal of 1132013310000 is 133102311.
It is a tau number, because it is divible by the number of its divisors (200).
It is a super-2 number, since 2×11320133100002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 130300 + ... + 1510299.
It is an arithmetic number, because the mean of its divisors is an integer number (19065871968).
Almost surely, 21132013310000 is an apocalyptic number.
1132013310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1132013310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1906587196800).
1132013310000 is an abundant number, since it is smaller than the sum of its proper divisors (2681161083600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1132013310000 is a wasteful number, since it uses less digits than its factorization.
1132013310000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1640653 (or 1640632 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 1132013310000 its reverse (133102311), we get a palindrome (1132146412311).
The spelling of 1132013310000 in words is "one trillion, one hundred thirty-two billion, thirteen million, three hundred ten thousand".
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