Base | Representation |
---|---|
bin | 10101000101011101… |
… | …11010111010001111 |
3 | 1002012220211212120012 |
4 | 22202232322322033 |
5 | 141140424043003 |
6 | 5111141543435 |
7 | 550344426554 |
oct | 124256727217 |
9 | 32186755505 |
10 | 11320143503 |
11 | 4889a203a9 |
12 | 223b114b7b |
13 | 10b5358c86 |
14 | 795608a2b |
15 | 463c2b8d8 |
hex | 2a2bbae8f |
11320143503 has 4 divisors (see below), whose sum is σ = 11505719688. Its totient is φ = 11134567320.
The previous prime is 11320143469. The next prime is 11320143517. The reversal of 11320143503 is 30534102311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30534102311 = 109 ⋅280129379.
It is a cyclic number.
It is not a de Polignac number, because 11320143503 - 218 = 11319881359 is a prime.
It is a super-2 number, since 2×113201435032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11320143553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92788001 + ... + 92788122.
It is an arithmetic number, because the mean of its divisors is an integer number (2876429922).
Almost surely, 211320143503 is an apocalyptic number.
11320143503 is a deficient number, since it is larger than the sum of its proper divisors (185576185).
11320143503 is an equidigital number, since it uses as much as digits as its factorization.
11320143503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 185576184.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 11320143503 its reverse (30534102311), we get a palindrome (41854245814).
The spelling of 11320143503 in words is "eleven billion, three hundred twenty million, one hundred forty-three thousand, five hundred three".
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