Base | Representation |
---|---|
bin | 10101000101011110… |
… | …01001110000001101 |
3 | 1002012220221221221222 |
4 | 22202233021300031 |
5 | 141140433014201 |
6 | 5111143133125 |
7 | 550345102040 |
oct | 124257116015 |
9 | 32186857858 |
10 | 11320204301 |
11 | 4889a6204a |
12 | 223b1441a5 |
13 | 10b537a853 |
14 | 795622c57 |
15 | 463c3e91b |
hex | 2a2bc9c0d |
11320204301 has 4 divisors (see below), whose sum is σ = 12937376352. Its totient is φ = 9703032252.
The previous prime is 11320204277. The next prime is 11320204319. The reversal of 11320204301 is 10340202311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11320204301 - 230 = 10246462477 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11320204301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11320204361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808586015 + ... + 808586028.
It is an arithmetic number, because the mean of its divisors is an integer number (3234344088).
Almost surely, 211320204301 is an apocalyptic number.
It is an amenable number.
11320204301 is a deficient number, since it is larger than the sum of its proper divisors (1617172051).
11320204301 is an equidigital number, since it uses as much as digits as its factorization.
11320204301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1617172050.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 11320204301 its reverse (10340202311), we get a palindrome (21660406612).
The spelling of 11320204301 in words is "eleven billion, three hundred twenty million, two hundred four thousand, three hundred one".
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