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11320204301 = 71617172043
BaseRepresentation
bin10101000101011110…
…01001110000001101
31002012220221221221222
422202233021300031
5141140433014201
65111143133125
7550345102040
oct124257116015
932186857858
1011320204301
114889a6204a
12223b1441a5
1310b537a853
14795622c57
15463c3e91b
hex2a2bc9c0d

11320204301 has 4 divisors (see below), whose sum is σ = 12937376352. Its totient is φ = 9703032252.

The previous prime is 11320204277. The next prime is 11320204319. The reversal of 11320204301 is 10340202311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11320204301 - 230 = 10246462477 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11320204301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11320204361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808586015 + ... + 808586028.

It is an arithmetic number, because the mean of its divisors is an integer number (3234344088).

Almost surely, 211320204301 is an apocalyptic number.

It is an amenable number.

11320204301 is a deficient number, since it is larger than the sum of its proper divisors (1617172051).

11320204301 is an equidigital number, since it uses as much as digits as its factorization.

11320204301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1617172050.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11320204301 its reverse (10340202311), we get a palindrome (21660406612).

The spelling of 11320204301 in words is "eleven billion, three hundred twenty million, two hundred four thousand, three hundred one".

Divisors: 1 7 1617172043 11320204301