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11320344241132 = 223079218521369
BaseRepresentation
bin1010010010111011100100…
…0110001110001111101100
31111002012210020212020100211
42210232321012032033230
52440433031111204012
640024254440232204
72245603453253233
oct244567106161754
944065706766324
1011320344241132
113674a27226733
121329b6046b664
13641672048464
142b1c9c5abb1a
15149704e316a7
hexa4bb918e3ec

11320344241132 has 12 divisors (see below), whose sum is σ = 19875132073720. Its totient is φ = 5641735077216.

The previous prime is 11320344241097. The next prime is 11320344241139. The reversal of 11320344241132 is 23114244302311.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 11320344241094 and 11320344241103.

It is not an unprimeable number, because it can be changed into a prime (11320344241139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4609259457 + ... + 4609261912.

Almost surely, 211320344241132 is an apocalyptic number.

It is an amenable number.

11320344241132 is a deficient number, since it is larger than the sum of its proper divisors (8554787832588).

11320344241132 is a wasteful number, since it uses less digits than its factorization.

11320344241132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9218521680 (or 9218521678 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 11320344241132 its reverse (23114244302311), we get a palindrome (34434588543443).

The spelling of 11320344241132 in words is "eleven trillion, three hundred twenty billion, three hundred forty-four million, two hundred forty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 307 614 1228 9218521369 18437042738 36874085476 2830086060283 5660172120566 11320344241132