Base | Representation |
---|---|
bin | 110100101101110001… |
… | …1000010011010000101 |
3 | 101211012110021221212102 |
4 | 1221123203002122011 |
5 | 3323320443430003 |
6 | 124001121201445 |
7 | 11115220100234 |
oct | 1513343023205 |
9 | 354173257772 |
10 | 113205061253 |
11 | 44012340069 |
12 | 19b34190285 |
13 | a8a151b35b |
14 | 569cb28b1b |
15 | 2e28695588 |
hex | 1a5b8c2685 |
113205061253 has 4 divisors (see below), whose sum is σ = 113209288608. Its totient is φ = 113200833900.
The previous prime is 113205061219. The next prime is 113205061303. The reversal of 113205061253 is 352160502311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113205061253 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113205061553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2073251 + ... + 2127152.
It is an arithmetic number, because the mean of its divisors is an integer number (28302322152).
Almost surely, 2113205061253 is an apocalyptic number.
It is an amenable number.
113205061253 is a deficient number, since it is larger than the sum of its proper divisors (4227355).
113205061253 is an equidigital number, since it uses as much as digits as its factorization.
113205061253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4227354.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 113205061253 its reverse (352160502311), we get a palindrome (465365563564).
The spelling of 113205061253 in words is "one hundred thirteen billion, two hundred five million, sixty-one thousand, two hundred fifty-three".
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