Base | Representation |
---|---|
bin | 10000011110010110001… |
… | …011001100111110110111 |
3 | 11000020010201012100002201 |
4 | 100132112023030332313 |
5 | 122022013023334012 |
6 | 2224024440245331 |
7 | 144535251346345 |
oct | 20362613147667 |
9 | 4006121170081 |
10 | 1132095918007 |
11 | 3a71346a526a |
12 | 1634a8770847 |
13 | 829aa45c232 |
14 | 3cb18018995 |
15 | 1e6ad5d7857 |
hex | 107962ccfb7 |
1132095918007 has 2 divisors, whose sum is σ = 1132095918008. Its totient is φ = 1132095918006.
The previous prime is 1132095917999. The next prime is 1132095918029. The reversal of 1132095918007 is 7008195902311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1132095918007 - 23 = 1132095917999 is a prime.
It is a super-2 number, since 2×11320959180072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1132095918307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566047959003 + 566047959004.
It is an arithmetic number, because the mean of its divisors is an integer number (566047959004).
Almost surely, 21132095918007 is an apocalyptic number.
1132095918007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132095918007 is an equidigital number, since it uses as much as digits as its factorization.
1132095918007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 136080, while the sum is 46.
The spelling of 1132095918007 in words is "one trillion, one hundred thirty-two billion, ninety-five million, nine hundred eighteen thousand, seven".
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