11321000000113 has 2 divisors, whose sum is σ = 11321000000114. Its totient is φ = 11321000000112.

The previous prime is 11321000000087. The next prime is 11321000000119. The reversal of 11321000000113 is 31100000012311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10732483946209 + 588516053904 = 3276047^2 + 767148^2 .

It is a cyclic number.

It is not a de Polignac number, because 11321000000113 - 2⁵ = 11321000000081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11321000000093 and 11321000000102.

It is not a weakly prime, because it can be changed into another prime (11321000000119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660500000056 + 5660500000057.

It is an arithmetic number, because the mean of its divisors is an integer number (5660500000057).

Almost surely, 2^{11321000000113} is an apocalyptic number.

It is an amenable number.

11321000000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11321000000113 is an equidigital number, since it uses as much as digits as its factorization.

11321000000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11321000000113 its reverse (31100000012311), we get a palindrome (42421000012424).

The spelling of 11321000000113 in words is "eleven trillion, three hundred twenty-one billion, one hundred thirteen", and thus it is an aban number.