Base | Representation |
---|---|
bin | 10000011110010110011… |
… | …110101101010101111011 |
3 | 11000020011001211010012121 |
4 | 100132112132231111323 |
5 | 122022020331000131 |
6 | 2224025142022111 |
7 | 144535342664026 |
oct | 20362636552573 |
9 | 4006131733177 |
10 | 1132101031291 |
11 | 3a7137577a1a |
12 | 1634aa417937 |
13 | 829ab52c749 |
14 | 3cb1898a1bd |
15 | 1e6adc97911 |
hex | 107967ad57b |
1132101031291 has 2 divisors, whose sum is σ = 1132101031292. Its totient is φ = 1132101031290.
The previous prime is 1132101031289. The next prime is 1132101031309. The reversal of 1132101031291 is 1921301012311.
It is a weak prime.
It is an emirp because it is prime and its reverse (1921301012311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1132101031291 - 21 = 1132101031289 is a prime.
It is a super-3 number, since 3×11321010312913 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 1132101031289, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1132101031091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566050515645 + 566050515646.
It is an arithmetic number, because the mean of its divisors is an integer number (566050515646).
Almost surely, 21132101031291 is an apocalyptic number.
1132101031291 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132101031291 is an equidigital number, since it uses as much as digits as its factorization.
1132101031291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 1132101031291 in words is "one trillion, one hundred thirty-two billion, one hundred one million, thirty-one thousand, two hundred ninety-one".
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