11321041124117 has 2 divisors, whose sum is σ = 11321041124118. Its totient is φ = 11321041124116.

The previous prime is 11321041124069. The next prime is 11321041124119. The reversal of 11321041124117 is 71142114012311.

11321041124117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11254374400516 + 66666723601 = 3354754^2 + 258199^2 .

It is a cyclic number.

It is not a de Polignac number, because 11321041124117 - 2²⁸ = 11320772688661 is a prime.

Together with 11321041124119, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11321041124117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11321041124119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660520562058 + 5660520562059.

It is an arithmetic number, because the mean of its divisors is an integer number (5660520562059).

Almost surely, 2^{11321041124117} is an apocalyptic number.

It is an amenable number.

11321041124117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11321041124117 is an equidigital number, since it uses as much as digits as its factorization.

11321041124117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 29.

Adding to 11321041124117 its reverse (71142114012311), we get a palindrome (82463155136428).

The spelling of 11321041124117 in words is "eleven trillion, three hundred twenty-one billion, forty-one million, one hundred twenty-four thousand, one hundred seventeen".