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11321043343 = 50232253841
BaseRepresentation
bin10101000101100100…
…10110100110001111
31002012222112120220121
422202302112212033
5141141141341333
65111213125411
7550355165161
oct124262264617
932188476817
1011321043343
11488a485475
12223b489867
1310b55b271c
147957a0931
15463d5832d
hex2a2c9698f

11321043343 has 4 divisors (see below), whose sum is σ = 11323302208. Its totient is φ = 11318784480.

The previous prime is 11321043337. The next prime is 11321043373. The reversal of 11321043343 is 34334012311.

11321043343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11321043343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11321043313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1121898 + ... + 1131943.

It is an arithmetic number, because the mean of its divisors is an integer number (2830825552).

Almost surely, 211321043343 is an apocalyptic number.

11321043343 is a deficient number, since it is larger than the sum of its proper divisors (2258865).

11321043343 is an equidigital number, since it uses as much as digits as its factorization.

11321043343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2258864.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11321043343 its reverse (34334012311), we get a palindrome (45655055654).

The spelling of 11321043343 in words is "eleven billion, three hundred twenty-one million, forty-three thousand, three hundred forty-three".

Divisors: 1 5023 2253841 11321043343