Base | Representation |
---|---|
bin | 10101000101101100… |
… | …00000011100101001 |
3 | 1002020001100020211112 |
4 | 22202312000130221 |
5 | 141141413014233 |
6 | 5111245440105 |
7 | 550366264556 |
oct | 124266003451 |
9 | 32201306745 |
10 | 11322001193 |
11 | 488aa7a088 |
12 | 223b870035 |
13 | 10b58596b9 |
14 | 79596da2d |
15 | 463e97048 |
hex | 2a2d80729 |
11322001193 has 2 divisors, whose sum is σ = 11322001194. Its totient is φ = 11322001192.
The previous prime is 11322001177. The next prime is 11322001237. The reversal of 11322001193 is 39110022311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9439482649 + 1882518544 = 97157^2 + 43388^2 .
It is a cyclic number.
It is not a de Polignac number, because 11322001193 - 24 = 11322001177 is a prime.
It is a super-2 number, since 2×113220011932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11322001153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661000596 + 5661000597.
It is an arithmetic number, because the mean of its divisors is an integer number (5661000597).
Almost surely, 211322001193 is an apocalyptic number.
It is an amenable number.
11322001193 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322001193 is an equidigital number, since it uses as much as digits as its factorization.
11322001193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
The spelling of 11322001193 in words is "eleven billion, three hundred twenty-two million, one thousand, one hundred ninety-three".
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