Base | Representation |
---|---|
bin | 1010010011000001110110… |
… | …0110000100101001010111 |
3 | 1111002101010202111111210212 |
4 | 2210300131212010221113 |
5 | 2441000004224441043 |
6 | 40025134030440035 |
7 | 2245663315522634 |
oct | 244603546045127 |
9 | 44071122444725 |
10 | 11322030312023 |
11 | 3675711a45752 |
12 | 132a35106301b |
13 | 641880458942 |
14 | 2b1dbc4a918b |
15 | 1497a2e83018 |
hex | a4c1d984a57 |
11322030312023 has 2 divisors, whose sum is σ = 11322030312024. Its totient is φ = 11322030312022.
The previous prime is 11322030312007. The next prime is 11322030312053. The reversal of 11322030312023 is 32021303022311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11322030312023 - 24 = 11322030312007 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11322030312023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11322030312053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661015156011 + 5661015156012.
It is an arithmetic number, because the mean of its divisors is an integer number (5661015156012).
Almost surely, 211322030312023 is an apocalyptic number.
11322030312023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322030312023 is an equidigital number, since it uses as much as digits as its factorization.
11322030312023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11322030312023 its reverse (32021303022311), we get a palindrome (43343333334334).
The spelling of 11322030312023 in words is "eleven trillion, three hundred twenty-two billion, thirty million, three hundred twelve thousand, twenty-three".
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