Base | Representation |
---|---|
bin | 110100101110010000… |
… | …0010011010001101011 |
3 | 101211020120111212212201 |
4 | 1221130200103101223 |
5 | 3323334101334011 |
6 | 124002453321031 |
7 | 11115503436106 |
oct | 1513440232153 |
9 | 354216455781 |
10 | 113221121131 |
11 | 4402040a098 |
12 | 19b39636177 |
13 | a8a4952241 |
14 | 56a0d0973d |
15 | 2e29cb8cc1 |
hex | 1a5c81346b |
113221121131 has 2 divisors, whose sum is σ = 113221121132. Its totient is φ = 113221121130.
The previous prime is 113221121107. The next prime is 113221121183. The reversal of 113221121131 is 131121122311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113221121131 is a prime.
It is a super-2 number, since 2×1132211211312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113221121099 and 113221121108.
It is not a weakly prime, because it can be changed into another prime (113221121191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56610560565 + 56610560566.
It is an arithmetic number, because the mean of its divisors is an integer number (56610560566).
Almost surely, 2113221121131 is an apocalyptic number.
113221121131 is a deficient number, since it is larger than the sum of its proper divisors (1).
113221121131 is an equidigital number, since it uses as much as digits as its factorization.
113221121131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72, while the sum is 19.
Adding to 113221121131 its reverse (131121122311), we get a palindrome (244342243442).
The spelling of 113221121131 in words is "one hundred thirteen billion, two hundred twenty-one million, one hundred twenty-one thousand, one hundred thirty-one".
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