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113221211141 = 671689868823
BaseRepresentation
bin110100101110010000…
…0101001010000000101
3101211020120200110100102
41221130200221100011
53323334112224031
6124002455253445
711115504262403
oct1513440512005
9354216613312
10113221211141
1144020470785
1219b3967a285
13a8a49841bc
1456a0d30473
152e29cd57cb
hex1a5c829405

113221211141 has 4 divisors (see below), whose sum is σ = 114911080032. Its totient is φ = 111531342252.

The previous prime is 113221211111. The next prime is 113221211167. The reversal of 113221211141 is 141112122311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 141112122311 = 839168190849.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113221211141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113221211111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 844934345 + ... + 844934478.

It is an arithmetic number, because the mean of its divisors is an integer number (28727770008).

Almost surely, 2113221211141 is an apocalyptic number.

It is an amenable number.

113221211141 is a deficient number, since it is larger than the sum of its proper divisors (1689868891).

113221211141 is an equidigital number, since it uses as much as digits as its factorization.

113221211141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1689868890.

The product of its digits is 96, while the sum is 20.

Adding to 113221211141 its reverse (141112122311), we get a palindrome (254333333452).

The spelling of 113221211141 in words is "one hundred thirteen billion, two hundred twenty-one million, two hundred eleven thousand, one hundred forty-one".

Divisors: 1 67 1689868823 113221211141