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11322220020047 is a prime number
BaseRepresentation
bin1010010011000010100011…
…1001110000000101001111
31111002101121222110200021222
42210300220321300011033
52441000401311120142
640025204524513555
72246001111153356
oct244605071600517
944071558420258
1011322220020047
1136757aa039142
12132a3a46ab8bb
136418b084b501
142b1dd976c99d
151497b4957bd2
hexa4c28e7014f

11322220020047 has 2 divisors, whose sum is σ = 11322220020048. Its totient is φ = 11322220020046.

The previous prime is 11322220019989. The next prime is 11322220020049. The reversal of 11322220020047 is 74002002222311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11322220020047 - 28 = 11322220019791 is a prime.

Together with 11322220020049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11322220019998 and 11322220020025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11322220020049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661110010023 + 5661110010024.

It is an arithmetic number, because the mean of its divisors is an integer number (5661110010024).

Almost surely, 211322220020047 is an apocalyptic number.

11322220020047 is a deficient number, since it is larger than the sum of its proper divisors (1).

11322220020047 is an equidigital number, since it uses as much as digits as its factorization.

11322220020047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2688, while the sum is 26.

Adding to 11322220020047 its reverse (74002002222311), we get a palindrome (85324222242358).

The spelling of 11322220020047 in words is "eleven trillion, three hundred twenty-two billion, two hundred twenty million, twenty thousand, forty-seven".