113230044041 has 2 divisors, whose sum is σ = 113230044042. Its totient is φ = 113230044040.

The previous prime is 113230044029. The next prime is 113230044043. The reversal of 113230044041 is 140440032311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111971213641 + 1258830400 = 334621^2 + 35480^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113230044041 is a prime.

Together with 113230044043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113230043998 and 113230044016.

It is not a weakly prime, because it can be changed into another prime (113230044043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615022020 + 56615022021.

It is an arithmetic number, because the mean of its divisors is an integer number (56615022021).

Almost surely, 2^113230044041 is an apocalyptic number.

It is an amenable number.

113230044041 is a deficient number, since it is larger than the sum of its proper divisors (1).

113230044041 is an equidigital number, since it uses as much as digits as its factorization.

113230044041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 113230044041 its reverse (140440032311), we get a palindrome (253670076352).

The spelling of 113230044041 in words is "one hundred thirteen billion, two hundred thirty million, forty-four thousand, forty-one".