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113230101121 is a prime number
BaseRepresentation
bin110100101110100001…
…0100011101010000001
3101211021012102010002221
41221131002203222001
53323343401213441
6124003414011041
711115642656614
oct1513502435201
9354235363087
10113230101121
1144025492975
1219b40646a81
13a8a6777747
1456a21a617b
152e2a98e8d1
hex1a5d0a3a81

113230101121 has 2 divisors, whose sum is σ = 113230101122. Its totient is φ = 113230101120.

The previous prime is 113230101119. The next prime is 113230101161. The reversal of 113230101121 is 121101032311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 60759785025 + 52470316096 = 246495^2 + 229064^2 .

It is a cyclic number.

It is not a de Polignac number, because 113230101121 - 21 = 113230101119 is a prime.

Together with 113230101119, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 113230101095 and 113230101104.

It is not a weakly prime, because it can be changed into another prime (113230101161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615050560 + 56615050561.

It is an arithmetic number, because the mean of its divisors is an integer number (56615050561).

Almost surely, 2113230101121 is an apocalyptic number.

It is an amenable number.

113230101121 is a deficient number, since it is larger than the sum of its proper divisors (1).

113230101121 is an equidigital number, since it uses as much as digits as its factorization.

113230101121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 113230101121 its reverse (121101032311), we get a palindrome (234331133432).

The spelling of 113230101121 in words is "one hundred thirteen billion, two hundred thirty million, one hundred one thousand, one hundred twenty-one".