Base | Representation |
---|---|
bin | 110100101110100001… |
… | …0101000010011100011 |
3 | 101211021012110002020012 |
4 | 1221131002220103203 |
5 | 3323343402321123 |
6 | 124003414235135 |
7 | 11115643066256 |
oct | 1513502502343 |
9 | 354235402205 |
10 | 113230120163 |
11 | 440254a6206 |
12 | 19b40655aab |
13 | a8a6783304 |
14 | 56a21ad09d |
15 | 2e2a995378 |
hex | 1a5d0a84e3 |
113230120163 has 2 divisors, whose sum is σ = 113230120164. Its totient is φ = 113230120162.
The previous prime is 113230120153. The next prime is 113230120181. The reversal of 113230120163 is 361021032311.
It is a weak prime.
It is an emirp because it is prime and its reverse (361021032311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113230120163 - 210 = 113230119139 is a prime.
It is a super-2 number, since 2×1132301201632 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113230120103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615060081 + 56615060082.
It is an arithmetic number, because the mean of its divisors is an integer number (56615060082).
Almost surely, 2113230120163 is an apocalyptic number.
113230120163 is a deficient number, since it is larger than the sum of its proper divisors (1).
113230120163 is an equidigital number, since it uses as much as digits as its factorization.
113230120163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 113230120163 its reverse (361021032311), we get a palindrome (474251152474).
The spelling of 113230120163 in words is "one hundred thirteen billion, two hundred thirty million, one hundred twenty thousand, one hundred sixty-three".
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